Nonlinear Systems Relations and Functions I. Hand Back Midterm I II. Homework III. Nonlinear Systems To solve a system of two equations and two unknowns when the equations are not linear, we use the methods of substitution or elimination and hope that the resulting equation becomes a hidden quadratic or other solvable equation. Example: x2 - y = 0 x2 - 2x + y = 6 We use substitution: solving for y in the first equation we get: y = x2 Putting it into the second equation, we have: x2 - 2x + x2 = 6 so that 2x2 -2x - 6 = 0 or x2 - x - 3 = 0 The quadratic formula gives us: (1 +- sqrt(1 + 12))/2 so x = 2.3 or x = -1.3 since y= x2 we get y = 5.29 or y = 1.69 We arrive at the two points: (2.3,5.29) and (-1.3,1.69) Example 2: x2 + y2 = 29 x2 - y2 = 3 We use elimination: adding the two equations, we have 2x2 = 32 x2 = 16 x = 4 or x = -4 Putting x = 4 into equation 2, we have: 16 - y2 = 3 -y2 = -13 y = sqrt(13) or y = -sqrt 13 Putting x = -4 into equation 2, we have: 16 - y2 = 3 -y2 = -13 y = sqrt(13) or y = -sqrt 13 Therefore we obtain the four points: (4,sqrt(13)), (4,-sqrt(13)), (-4,sqrt(13)), (-4,-sqrt(13))
The class will try the following examples: 1) x2 - y2 = 4 2x2 + y2 = 16 2) y - 2x2 = 0 x2 +6x - y = 6 3) x2 - y2 = 21 x2 + xy - y2 = 31 IV. Relations A relation is a rule that takes an input from a set (called the range) and gives one or more outputs of another set (called the range). Examples: (0,0), (4,4), (0,3), (2,1) y = 2x Arrow notation will be given. We will show how the graph of a circle is a relation. V. Functions A function is a relation such that for every input there is exactly one output. Example: (2,1), (3,4), (5,7) Arrow diagrams will also be given y = x2 VI. Determining the Domain of a Function Rule 1) The domain of a polynomial is the set of all real numbers. Example: for f(x) = 3x2 + 2x - 1 the domain is the set of all real numbers. ( more examples will be given in class) Rule 2) The domain of a rational function (poly)/(poly) is the set of all real numbers except where the denominator is 0 Example: For f(x) = (x - 1)/(x + 1) the domain is all real numbers except where x = -1. ( more examples will be given in class) Rule 3) The domain of a square function is all real numbers that make the inside of the square root positive. Example: Find the domain of sqrt(x2 - x - 6): Solution: We set up the inequality x2 - x - 6 > 0 and use our steps of quadratic inequalities to solve. Factoring we get (x - 3)(x + 2) > 0 Putting -2 and 3 on a number line, gives three regions. The table shows
Hence the solution is (-infinity,-2] U [3,infinity) VII The Vertical Line Test If every vertical line passes through the graph at most once then the graph is the graph of a function. Examples will be given in class.
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