Intersection of Lines: Substitution vs Elimination
Recall that if we want to find the intersection point of two lines, we have
two choices: substitution and elimination.
Example: (Substitution)
Solve
x + 2y = 5
4x - 3y = -2
We use the first equation to solve for x:
x = 5 - 2y
then we plug this into the second equation to get
4(5 - 2y) - 3y = -2
-11y + 20 = -2
y = 2
stick this back into the equation for x to get:
x = 5 - 2(2) = 1.
Example: (Elimination)
Solve
2x + 5y = 19
3x - 5y = -9
We add the equation to get
5x = 10,
x = 2
Hence
2(2) + 5y = 19
y = 3.
Intersection of Other Curves
Example: Substitution
Find the intersection of the curves
x2 + y2 = 25
and
y = 1/3 x + 3
We use the method of substitution to arrive at
x2 + (1/3 x + 3)2 = 25
x2 + 1/9 x2 + 2x + 9 = 25
10x2 + 18x - 144 = 0
5x2 + 9x - 72 = 0
(5x + 24)(x - 3) = 0
x = -24/5
or
x = 3
y = (1/3)(-24/5 )+ 3
or y = 1/3(3) + 3
y = -7/5 or 4.
We get the points
(-24/5,-7/5)
and (3,4)
Example: Elimination
x2 + 2y2 = 18
2x2 + y2 = 15
We multiply the first equation by 2 and subtract the second equation to get:
3y2 = 21
y2 = 7
y =
or
y = -
Substituting back into the first equation, we get:
x2 + 2(7) = 18
x = 2
or x = -2,
hence we get the four points:
(2,),
(-2,),
(2,-),
(-2,-).
Example: Using a Graphing Calculator
We will use a graphing calculator to find the intersection of
y2 + 16x = 0
and
y2 +
9x2 -18x = 18.
To find the intersection we just use the intersection function on the graphing
calculator.
Example
We will use the intercept method to solve
(x - 7)(x + 4) = (x + 1)2
We find the intersection of the two curves
y = (x - 7)(x + 4)
and
y = (x + 1)2